How To Solve A Word Problem In Algebra

How To Solve A Word Problem In Algebra-3
This should result in the following equations: K= ¾ Z, S = ⅔ Z, K = S 15Taking the equation K=S 15 students need to replace the K with K= ¾ Z and the S with S= ⅔ Z thus creating the equation ¾ Z= ⅔ Z 15Students then need to recognise and multiply each of the terms by the common denominator 12, and then solve the resulting equation 9Z= 8Z 15 ∴ Z = 15Students should first review the process of writing algebraic expressions and equations from a worded description or rule.

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You would be expected to know that "time and a half" means dollars for every over-time hour.For instance, suppose you're told that "Shelby worked eight hours MTTh F and six hours WSat".You would be expected to understand that this meant that she worked eight hours for each of the four days Monday, Tuesday, Thursday, and Friday; and six hours for each of the two days Wednesday and Saturday.You'll also be expected to know that "perimeter" indicates the length around the outside of a flat shape such as a rectangle (so you'll probably be adding lengths) and that "area" indicates the size of the insides of the flat shape (so you'll probably be multiplying length by width, or applying some other formula).And "volume" is the insides of a three-dimensional shape, such as a cube or sphere (so you'll probably be multiplying).When you’re solving algebra word problems, it’s smart to have a plan of attack ready to follow.Solving word problems may seem difficult, but when you read through the problem and can figure out what the specific equation is, it’s no harder than a regular algebra problem.But figuring out the actual equation can seem nearly impossible. Be advised, however: To learn "how to do" word problems, you will need to practice, practice, practice.The first step to effectively translating and solving word problems is to read the problem entirely.Everything to the right of the equal sign (or inequality) is yet another expression. To keep these two terms separate, simply ask yourself if you can answer with a true/false. Simply stated, an expression is a combination of numbers, variables (letters) and operations. If so, you have an equation, not an expression which would have a numerical value.


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