Solving Gas Law Problems

The Ideal Gas Law can easily be reduced to Charles’, Boyle’s, or Avogadro’s Law.For example, suppose that n and T are held constant.Rather than remember all of the possible relationships between P, V, n, and T, and have to deal with a host of different “constants,” it would be nice to have a single relationship with a constant of proportionality that was really constant; that is, one whose value did not depend on what the other parameters’ values were.

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In the last section we saw that Charles’ Law relates the volume of a gas to its temperature; Boyle’s Law relates volume to pressure; and Avogadro’s Law relates volume to the number of moles of gas present, as well as a number of other relationships between P, V, n, and T.

In particular, we saw that volume is directly proportional to the temperature (in Kelvins!

Our answer will be in units of liters because those are the volume units for this value of the gas constant.

Now, substituting the values of n, R, T, and P into the solved equation, we find that the volume is 8.6 liters.

In it, you will measure n, T, P, and V for a sample of hydrogen gas, then use these values to compute the value of the gas constant, R.

The actual value of R will depend on the units that you use for P and V (n is always in moles and T in Kelvins).What will the pressure become if the gas is heated to 350 K and the volume is increased to 500 m L?” For problems of the first type, all you need to do is to solve the Ideal Gas Law for the variable whose value you are trying to find, then substitute values for the other known variables and compute the answer. If you’re a little rusty, it might be a good idea to review the techniques used to solve simple algebraic equations.The symbol “R” in this equation is a constant called “the gas constant” and its value can be computed by measuring the temperature, volume, and pressure of a known quantity of an ideal gas and substituting these values into the Ideal Gas Law solved for R.In fact, this is the bases of the laboratory exercise for this lesson.The two operations you will most often use are multiplying both sides of an equation by some quantity and dividing both sides of an equation by some quantity in order to solve it.At times you may also need to add or subtract quantities from both sides of an equation.Note how the units cancel to give the units of the answer, liters.Checking to make sure that the units cancel properly to give the appropriate units for the answer (in this case, liters for a volume) is a good way to check that you’ve done the algebra correctly and a valuable habit to get into.) and the number of moles of gas, and inversely proportional to pressure.In each case, there was a constant of proportionality whose value depending on the values of the quantities that were being held constant.


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