# Solving Projectile Problems

"Find this stuff." And you're just gonna have to know that okay, if I run off of a cliff horizontally or something gets shot horizontally, that means there is no vertical velocity to start with, I'm gonna have to plug this initial velocity in the y direction as zero. Don't fall for it now you know how to deal with it. But we can't use this to solve directly for the displacement in the x direction.

- [Instructor] Let's talk about how to handle a horizontally launched projectile problem.

These, technically speaking, if you already know how to do projectile problems, there is nothing new, except that there's one aspect of these problems that people get stumped by all of the time.

So if the initial velocity of the object for a projectile is completely horizontal, then that object is a horizontally launched projectile. They're gonna run but they don't jump off the cliff, they just run straight off of the cliff 'cause they're kind of nervous. Alright, fish over here, person splashed into the water.

Let's say they run off of this cliff with five meters per second of initial velocity, straight off the cliff. So 30 meters tall, they launch, they fly through the air, there's water down here, so they initially went this way, and they start to fall down, and they do something like pschhh, and then they splash in the water, hopefully they don't hit any boats or fish down here. We want to know, here's the question you might get asked: how far did this person go horizontally before striking the water?

So this person just ran horizontally straight off the cliff and then they start to gain velocity.

So they're gonna gain vertical velocity downward and maybe more vertical velocity because gravity keeps pulling, and then even more, this might go off the screen but it's gonna be really big. What we know is that horizontally this person started off with an initial velocity.

This person was not launched vertically up or vertically down, this person was just launched straight horizontally, and so the initial velocity in the vertical direction is just zero. They're like "hold on a minute." They're like, this person is gonna start gaining, alright, this person is gonna start gaining velocity right when they leave the cliff, this starts getting bigger and bigger and bigger in the downward direction. We're talking about right as you leave the cliff.

That moment you left the cliff there was only horizontal velocity, which means you started with no initial vertical velocity.

They want to say that the initial velocity in the y direction is five meters per second.

I mean people are just dying to stick these five meters per second into here because that's the velocity that you were given. That's why this is called horizontally launched projectile motion, not vertically launched projectile motion. The initial velocity in the vertical direction here was zero, there was no initial vertical velocity.

• ###### What's an easy and reliable way to solve confusing projectile motion.

Background Did IBDP higher level physics, got 7 points and currently giving part-time physics tuition. Here is the answer to your question. In general, while answering projectile motion questions you should always list down the variables p.…

• ###### Solving Projectile Motion Using Energy - Clutch Prep

Video explaining Solving Projectile Motion Using Energy for Physics. This is one of many videos provided by Clutch Prep to prepare you to succeed in your…

• ###### Non-Horizontally Launched Projectiles – Problem-Solving

And problems can often be simplified by the use of short procedures as the one above. However, not all problems can be solved with the above procedure. While steps 1, 2 and 3 above are critical to your success in solving non-horizontally launched projectile problems, there will always be a problem that doesn’t “fit the mold.”…

Projectile Motion and Quadratic Functions I. ASSESSSMENT TASK OVERVIEW & PURPOSE The student will examine the path of a projectile and explain the motion using a quadratic function. Neglecting air resistance, projectiles follow the path of a parabola in nature.…

• ###### Strategies for Solving Problems - harvard.edu

Possible solving problems which is inevitably an active task beyond the time you spend reading which is generally a more passive task. I have therefore included a very large number of problems/exercises in this book. However, if I’m going to throw all these problems at you, I should at least give you some general strategies for solving them.…

• ###### Physics - Solving a projectile trajectory problem - Mathematica

Begingroup\$ Your parametric plot is correct. FindRoot is solving the equation yt=0 for t, using the best guess of t=70 as a starting point. Once you've found the time at which the projectile hits the ground y=0 you can ask what it's x position was at that time as well.…